Base | Representation |
---|---|
bin | 11001111101000000010110… |
… | …001101100111001000110111 |
3 | 112222011000010102220110210121 |
4 | 121331000112031213020313 |
5 | 104430111212410303211 |
6 | 1042432433113432411 |
7 | 33020406304420666 |
oct | 3175002615471067 |
9 | 488130112813717 |
10 | 114143423525431 |
11 | 33407a5495a263 |
12 | 1097591570b707 |
13 | 4b8c8a9000971 |
14 | 20287dd440ddd |
15 | d2e1ebc42271 |
hex | 67d016367237 |
114143423525431 has 2 divisors, whose sum is σ = 114143423525432. Its totient is φ = 114143423525430.
The previous prime is 114143423525407. The next prime is 114143423525459. The reversal of 114143423525431 is 134525324341411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114143423525431 - 217 = 114143423394359 is a prime.
It is a super-2 number, since 2×1141434235254312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114143423525401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57071711762715 + 57071711762716.
It is an arithmetic number, because the mean of its divisors is an integer number (57071711762716).
Almost surely, 2114143423525431 is an apocalyptic number.
114143423525431 is a deficient number, since it is larger than the sum of its proper divisors (1).
114143423525431 is an equidigital number, since it uses as much as digits as its factorization.
114143423525431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 691200, while the sum is 43.
Adding to 114143423525431 its reverse (134525324341411), we get a palindrome (248668747866842).
The spelling of 114143423525431 in words is "one hundred fourteen trillion, one hundred forty-three billion, four hundred twenty-three million, five hundred twenty-five thousand, four hundred thirty-one".
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