11414421331 has 2 divisors, whose sum is σ = 11414421332. Its totient is φ = 11414421330.

The previous prime is 11414421289. The next prime is 11414421341. The reversal of 11414421331 is 13312441411.

It is a strong prime.

It is an emirp because it is prime and its reverse (13312441411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11414421331 - 2⁷ = 11414421203 is a prime.

It is a super-2 number, since 2×11414421331² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11414421296 and 11414421305.

It is not a weakly prime, because it can be changed into another prime (11414421341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707210665 + 5707210666.

It is an arithmetic number, because the mean of its divisors is an integer number (5707210666).

Almost surely, 2^11414421331 is an apocalyptic number.

11414421331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11414421331 is an equidigital number, since it uses as much as digits as its factorization.

11414421331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 25.

Adding to 11414421331 its reverse (13312441411), we get a palindrome (24726862742).

The spelling of 11414421331 in words is "eleven billion, four hundred fourteen million, four hundred twenty-one thousand, three hundred thirty-one".