Base | Representation |
---|---|
bin | 110101001001110001… |
… | …0011101001111010111 |
3 | 101220121220212222210201 |
4 | 1222103202131033113 |
5 | 3332231433324421 |
6 | 124234235201331 |
7 | 11150414446552 |
oct | 1522342351727 |
9 | 356556788721 |
10 | 114144433111 |
11 | 44454614045 |
12 | 1a1568a6247 |
13 | a9c101b6a7 |
14 | 574b7b3699 |
15 | 2e80d9cb91 |
hex | 1a9389d3d7 |
114144433111 has 2 divisors, whose sum is σ = 114144433112. Its totient is φ = 114144433110.
The previous prime is 114144433043. The next prime is 114144433127. The reversal of 114144433111 is 111334441411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114144433111 - 229 = 113607562199 is a prime.
It is a super-2 number, since 2×1141444331112 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 114144433111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114144433171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57072216555 + 57072216556.
It is an arithmetic number, because the mean of its divisors is an integer number (57072216556).
Almost surely, 2114144433111 is an apocalyptic number.
114144433111 is a deficient number, since it is larger than the sum of its proper divisors (1).
114144433111 is an equidigital number, since it uses as much as digits as its factorization.
114144433111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2304, while the sum is 28.
Adding to 114144433111 its reverse (111334441411), we get a palindrome (225478874522).
The spelling of 114144433111 in words is "one hundred fourteen billion, one hundred forty-four million, four hundred thirty-three thousand, one hundred eleven".
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