Base | Representation |
---|---|
bin | 10101010000101110… |
… | …11001011101000011 |
3 | 1002110111122211000011 |
4 | 22220113121131003 |
5 | 141334121443301 |
6 | 5124355205351 |
7 | 552602562064 |
oct | 125027313503 |
9 | 32414584004 |
10 | 11414640451 |
11 | 49282a3355 |
12 | 22668a6857 |
13 | 10cbac3a26 |
14 | 7a3da656b |
15 | 46c195a51 |
hex | 2a85d9743 |
11414640451 has 2 divisors, whose sum is σ = 11414640452. Its totient is φ = 11414640450.
The previous prime is 11414640437. The next prime is 11414640467. The reversal of 11414640451 is 15404641411.
It is a happy number.
11414640451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (15404641411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11414640451 - 215 = 11414607683 is a prime.
It is not a weakly prime, because it can be changed into another prime (11414650451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707320225 + 5707320226.
It is an arithmetic number, because the mean of its divisors is an integer number (5707320226).
Almost surely, 211414640451 is an apocalyptic number.
11414640451 is a deficient number, since it is larger than the sum of its proper divisors (1).
11414640451 is an equidigital number, since it uses as much as digits as its factorization.
11414640451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 31.
The spelling of 11414640451 in words is "eleven billion, four hundred fourteen million, six hundred forty thousand, four hundred fifty-one".
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