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11415043530031 is a prime number
BaseRepresentation
bin1010011000011100010110…
…0111010101110100101111
31111102021020000021112222011
42212013011213111310233
52444011002120430111
640135555410502051
72255465264033431
oct246070547256457
944367200245864
1011415043530031
113701102535059
12134438ab94927
1364a58460c94b
142b66c3650651
1514bde8b15021
hexa61c59d5d2f

11415043530031 has 2 divisors, whose sum is σ = 11415043530032. Its totient is φ = 11415043530030.

The previous prime is 11415043530019. The next prime is 11415043530061. The reversal of 11415043530031 is 13003534051411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11415043530031 - 25 = 11415043529999 is a prime.

It is a super-2 number, since 2×114150435300312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11415043529975 and 11415043530002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11415043530061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707521765015 + 5707521765016.

It is an arithmetic number, because the mean of its divisors is an integer number (5707521765016).

Almost surely, 211415043530031 is an apocalyptic number.

11415043530031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11415043530031 is an equidigital number, since it uses as much as digits as its factorization.

11415043530031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 11415043530031 its reverse (13003534051411), we get a palindrome (24418577581442).

The spelling of 11415043530031 in words is "eleven trillion, four hundred fifteen billion, forty-three million, five hundred thirty thousand, thirty-one".