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1141533542153 is a prime number
BaseRepresentation
bin10000100111001000101…
…100111000011100001001
311001010111102202022120202
4100213020230320130021
5122200330041322103
62232225133301545
7145321160003504
oct20471054703411
94033442668522
101141533542153
11400137a19a44
121652a13348b5
1383852795114
143d3715ca13b
151ea61e0a988
hex109c8b38709

1141533542153 has 2 divisors, whose sum is σ = 1141533542154. Its totient is φ = 1141533542152.

The previous prime is 1141533542141. The next prime is 1141533542161. The reversal of 1141533542153 is 3512453351411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 937959321289 + 203574220864 = 968483^2 + 451192^2 .

It is an emirp because it is prime and its reverse (3512453351411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1141533542153 - 24 = 1141533542137 is a prime.

It is not a weakly prime, because it can be changed into another prime (1141533542753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570766771076 + 570766771077.

It is an arithmetic number, because the mean of its divisors is an integer number (570766771077).

Almost surely, 21141533542153 is an apocalyptic number.

It is an amenable number.

1141533542153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141533542153 is an equidigital number, since it uses as much as digits as its factorization.

1141533542153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108000, while the sum is 38.

Adding to 1141533542153 its reverse (3512453351411), we get a palindrome (4653986893564).

The spelling of 1141533542153 in words is "one trillion, one hundred forty-one billion, five hundred thirty-three million, five hundred forty-two thousand, one hundred fifty-three".