1141543020130 has 8 divisors (see below), whose sum is σ = 2054777436252. Its totient is φ = 456617208048.

The previous prime is 1141543020073. The next prime is 1141543020131. The reversal of 1141543020130 is 310203451411.

It can be written as a sum of positive squares in 2 ways, for example, as 1126228215121 + 15314805009 = 1061239^2 + 123753^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1141543020095 and 1141543020104.

It is not an unprimeable number, because it can be changed into a prime (1141543020131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57077150997 + ... + 57077151016.

Almost surely, 2^{1141543020130} is an apocalyptic number.

1141543020130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1141543020130 is a deficient number, since it is larger than the sum of its proper divisors (913234416122).

1141543020130 is a wasteful number, since it uses less digits than its factorization.

1141543020130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114154302020.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1141543020130 its reverse (310203451411), we get a palindrome (1451746471541).

The spelling of 1141543020130 in words is "one trillion, one hundred forty-one billion, five hundred forty-three million, twenty thousand, one hundred thirty".