Base | Representation |
---|---|
bin | 10101010000110100… |
… | …11101101000101101 |
3 | 1002110120011122021201 |
4 | 22220122131220231 |
5 | 141334323202023 |
6 | 5124424325501 |
7 | 552612446611 |
oct | 125032355055 |
9 | 32416148251 |
10 | 11415444013 |
11 | 49287a2056 |
12 | 2267013891 |
13 | 10cc0156cc |
14 | 7a4135341 |
15 | 46c2a3bad |
hex | 2a869da2d |
11415444013 has 2 divisors, whose sum is σ = 11415444014. Its totient is φ = 11415444012.
The previous prime is 11415443993. The next prime is 11415444023. The reversal of 11415444013 is 31044451411.
11415444013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11100097449 + 315346564 = 105357^2 + 17758^2 .
It is a cyclic number.
It is not a de Polignac number, because 11415444013 - 225 = 11381889581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11415444023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707722006 + 5707722007.
It is an arithmetic number, because the mean of its divisors is an integer number (5707722007).
Almost surely, 211415444013 is an apocalyptic number.
It is an amenable number.
11415444013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11415444013 is an equidigital number, since it uses as much as digits as its factorization.
11415444013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 11415444013 its reverse (31044451411), we get a palindrome (42459895424).
The spelling of 11415444013 in words is "eleven billion, four hundred fifteen million, four hundred forty-four thousand, thirteen".
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