Base | Representation |
---|---|
bin | 10101010000111101… |
… | …00000001111110001 |
3 | 1002110122011110022212 |
4 | 22220132200033301 |
5 | 141340111101111 |
6 | 5124503141505 |
7 | 552624451061 |
oct | 125036401761 |
9 | 32418143285 |
10 | 11416503281 |
11 | 4929355987 |
12 | 2267444895 |
13 | 10cc2c68b1 |
14 | 7a432d3a1 |
15 | 46c41298b |
hex | 2a87a03f1 |
11416503281 has 2 divisors, whose sum is σ = 11416503282. Its totient is φ = 11416503280.
The previous prime is 11416503209. The next prime is 11416503337. The reversal of 11416503281 is 18230561411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10233143281 + 1183360000 = 101159^2 + 34400^2 .
It is an emirp because it is prime and its reverse (18230561411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11416503281 - 210 = 11416502257 is a prime.
It is a super-2 number, since 2×114165032812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11416503781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5708251640 + 5708251641.
It is an arithmetic number, because the mean of its divisors is an integer number (5708251641).
Almost surely, 211416503281 is an apocalyptic number.
It is an amenable number.
11416503281 is a deficient number, since it is larger than the sum of its proper divisors (1).
11416503281 is an equidigital number, since it uses as much as digits as its factorization.
11416503281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 32.
The spelling of 11416503281 in words is "eleven billion, four hundred sixteen million, five hundred three thousand, two hundred eighty-one".
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