Base | Representation |
---|---|
bin | 1010011000101010010001… |
… | …1010101100011101101111 |
3 | 1111102121212111222211111221 |
4 | 2212022210122230131233 |
5 | 2444041131033042223 |
6 | 40141414341124211 |
7 | 2255660023403401 |
oct | 246124432543557 |
9 | 44377774884457 |
10 | 11418781534063 |
11 | 3702750541892 |
12 | 13450529b9667 |
13 | 64aa2bb7b757 |
14 | 2b6959c84b71 |
15 | 14c066d86b5d |
hex | a62a46ac76f |
11418781534063 has 2 divisors, whose sum is σ = 11418781534064. Its totient is φ = 11418781534062.
The previous prime is 11418781534019. The next prime is 11418781534091. The reversal of 11418781534063 is 36043518781411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11418781534063 - 217 = 11418781402991 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11418781534063.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11418781532063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5709390767031 + 5709390767032.
It is an arithmetic number, because the mean of its divisors is an integer number (5709390767032).
Almost surely, 211418781534063 is an apocalyptic number.
11418781534063 is a deficient number, since it is larger than the sum of its proper divisors (1).
11418781534063 is an equidigital number, since it uses as much as digits as its factorization.
11418781534063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1935360, while the sum is 52.
The spelling of 11418781534063 in words is "eleven trillion, four hundred eighteen billion, seven hundred eighty-one million, five hundred thirty-four thousand, sixty-three".
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