Base | Representation |
---|---|
bin | 1010011000101111010011… |
… | …0110111111111110110000 |
3 | 1111102202100120111110220020 |
4 | 2212023310312333332300 |
5 | 2444101412032200222 |
6 | 40142200311443440 |
7 | 2256035331653301 |
oct | 246136466777660 |
9 | 44382316443806 |
10 | 11420131131312 |
11 | 3703283335212 |
12 | 134536a986580 |
13 | 64abb56606c7 |
14 | 2b6a471d67a8 |
15 | 14c0e55c265c |
hex | a62f4dbffb0 |
11420131131312 has 40 divisors (see below), whose sum is σ = 29525108169456. Its totient is φ = 3803729377536.
The previous prime is 11420131131307. The next prime is 11420131131319. The reversal of 11420131131312 is 21313113102411.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is not an unprimeable number, because it can be changed into a prime (11420131131319) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 93094303 + ... + 93216894.
Almost surely, 211420131131312 is an apocalyptic number.
11420131131312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11420131131312 is an abundant number, since it is smaller than the sum of its proper divisors (18104977038144).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11420131131312 is a wasteful number, since it uses less digits than its factorization.
11420131131312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 186312485 (or 186312479 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 11420131131312 its reverse (21313113102411), we get a palindrome (32733244233723).
The spelling of 11420131131312 in words is "eleven trillion, four hundred twenty billion, one hundred thirty-one million, one hundred thirty-one thousand, three hundred twelve".
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