Base | Representation |
---|---|
bin | 110101001011011101… |
… | …1111101111001111001 |
3 | 101220202220011212020002 |
4 | 1222112323331321321 |
5 | 3332341032432103 |
6 | 124244033242345 |
7 | 11152006220045 |
oct | 1522673757171 |
9 | 356686155202 |
10 | 114201452153 |
11 | 44483819318 |
12 | 1a171a033b5 |
13 | a9cca93879 |
14 | 57551b7025 |
15 | 2e85db2488 |
hex | 1a96efde79 |
114201452153 has 2 divisors, whose sum is σ = 114201452154. Its totient is φ = 114201452152.
The previous prime is 114201452129. The next prime is 114201452171. The reversal of 114201452153 is 351254102411.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 63074815609 + 51126636544 = 251147^2 + 226112^2 .
It is an emirp because it is prime and its reverse (351254102411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114201452153 - 212 = 114201448057 is a prime.
It is not a weakly prime, because it can be changed into another prime (114201452353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57100726076 + 57100726077.
It is an arithmetic number, because the mean of its divisors is an integer number (57100726077).
Almost surely, 2114201452153 is an apocalyptic number.
It is an amenable number.
114201452153 is a deficient number, since it is larger than the sum of its proper divisors (1).
114201452153 is an equidigital number, since it uses as much as digits as its factorization.
114201452153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 114201452153 its reverse (351254102411), we get a palindrome (465455554564).
The spelling of 114201452153 in words is "one hundred fourteen billion, two hundred one million, four hundred fifty-two thousand, one hundred fifty-three".
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