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11420221231 is a prime number
BaseRepresentation
bin10101010001011001…
…01011111100101111
31002110220011100101201
422220230223330233
5141342034034411
65125114550331
7553001164426
oct125054537457
932426140351
1011420221231
114930465271
1222687383a7
1310cccc8c73
147a4a1a2bd
1546c8e93c1
hex2a8b2bf2f

11420221231 has 2 divisors, whose sum is σ = 11420221232. Its totient is φ = 11420221230.

The previous prime is 11420221217. The next prime is 11420221243. The reversal of 11420221231 is 13212202411.

It is a strong prime.

It is an emirp because it is prime and its reverse (13212202411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11420221231 - 27 = 11420221103 is a prime.

It is a super-2 number, since 2×114202212312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11420221199 and 11420221208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11420221271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710110615 + 5710110616.

It is an arithmetic number, because the mean of its divisors is an integer number (5710110616).

Almost surely, 211420221231 is an apocalyptic number.

11420221231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11420221231 is an equidigital number, since it uses as much as digits as its factorization.

11420221231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11420221231 its reverse (13212202411), we get a palindrome (24632423642).

The spelling of 11420221231 in words is "eleven billion, four hundred twenty million, two hundred twenty-one thousand, two hundred thirty-one".