Base | Representation |
---|---|
bin | 10000100111100101111… |
… | …001001111101000010011 |
3 | 11001011202120100201101221 |
4 | 100213211321033220103 |
5 | 122202330432302011 |
6 | 2232345511105511 |
7 | 145336255033456 |
oct | 20474571175023 |
9 | 4034676321357 |
10 | 1142023322131 |
11 | 40036943598a |
12 | 1653b9372297 |
13 | 839000ac463 |
14 | 3d3ba68149d |
15 | 1ea8ee05971 |
hex | 109e5e4fa13 |
1142023322131 has 2 divisors, whose sum is σ = 1142023322132. Its totient is φ = 1142023322130.
The previous prime is 1142023322051. The next prime is 1142023322161. The reversal of 1142023322131 is 1312233202411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1142023322131 - 223 = 1142014933523 is a prime.
It is a super-2 number, since 2×11420233221312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1142023322096 and 1142023322105.
It is not a weakly prime, because it can be changed into another prime (1142023322161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571011661065 + 571011661066.
It is an arithmetic number, because the mean of its divisors is an integer number (571011661066).
Almost surely, 21142023322131 is an apocalyptic number.
1142023322131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1142023322131 is an equidigital number, since it uses as much as digits as its factorization.
1142023322131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1142023322131 its reverse (1312233202411), we get a palindrome (2454256524542).
The spelling of 1142023322131 in words is "one trillion, one hundred forty-two billion, twenty-three million, three hundred twenty-two thousand, one hundred thirty-one".
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