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1142023322131 is a prime number
BaseRepresentation
bin10000100111100101111…
…001001111101000010011
311001011202120100201101221
4100213211321033220103
5122202330432302011
62232345511105511
7145336255033456
oct20474571175023
94034676321357
101142023322131
1140036943598a
121653b9372297
13839000ac463
143d3ba68149d
151ea8ee05971
hex109e5e4fa13

1142023322131 has 2 divisors, whose sum is σ = 1142023322132. Its totient is φ = 1142023322130.

The previous prime is 1142023322051. The next prime is 1142023322161. The reversal of 1142023322131 is 1312233202411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1142023322131 - 223 = 1142014933523 is a prime.

It is a super-2 number, since 2×11420233221312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1142023322096 and 1142023322105.

It is not a weakly prime, because it can be changed into another prime (1142023322161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571011661065 + 571011661066.

It is an arithmetic number, because the mean of its divisors is an integer number (571011661066).

Almost surely, 21142023322131 is an apocalyptic number.

1142023322131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142023322131 is an equidigital number, since it uses as much as digits as its factorization.

1142023322131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1142023322131 its reverse (1312233202411), we get a palindrome (2454256524542).

The spelling of 1142023322131 in words is "one trillion, one hundred forty-two billion, twenty-three million, three hundred twenty-two thousand, one hundred thirty-one".