Base | Representation |
---|---|
bin | 10000100111100101111… |
… | …100101000101110000011 |
3 | 11001011202122000220011021 |
4 | 100213211330220232003 |
5 | 122202331144230311 |
6 | 2232345542130311 |
7 | 145336265426053 |
oct | 20474574505603 |
9 | 4034678026137 |
10 | 1142024211331 |
11 | 400369992a63 |
12 | 1653b9720997 |
13 | 83900331103 |
14 | 3d3ba833563 |
15 | 1ea9002e171 |
hex | 109e5f28b83 |
1142024211331 has 2 divisors, whose sum is σ = 1142024211332. Its totient is φ = 1142024211330.
The previous prime is 1142024211299. The next prime is 1142024211353. The reversal of 1142024211331 is 1331124202411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1142024211331 - 25 = 1142024211299 is a prime.
It is a super-2 number, since 2×11420242113312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1142024211296 and 1142024211305.
It is not a weakly prime, because it can be changed into another prime (1142024211371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571012105665 + 571012105666.
It is an arithmetic number, because the mean of its divisors is an integer number (571012105666).
Almost surely, 21142024211331 is an apocalyptic number.
1142024211331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1142024211331 is an equidigital number, since it uses as much as digits as its factorization.
1142024211331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1142024211331 its reverse (1331124202411), we get a palindrome (2473148413742).
The spelling of 1142024211331 in words is "one trillion, one hundred forty-two billion, twenty-four million, two hundred eleven thousand, three hundred thirty-one".
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