Base | Representation |
---|---|
bin | 10000100111101100111… |
… | …010111010111111100011 |
3 | 11001012001210011122201221 |
4 | 100213230322322333203 |
5 | 122203101121434103 |
6 | 2232405321435511 |
7 | 145342216015645 |
oct | 20475472727743 |
9 | 4035053148657 |
10 | 1142141202403 |
11 | 400419a2a0a3 |
12 | 16543093bb97 |
13 | 8391b6435b6 |
14 | 3d3cc1a8895 |
15 | 1ea9a43d1bd |
hex | 109ecebafe3 |
1142141202403 has 2 divisors, whose sum is σ = 1142141202404. Its totient is φ = 1142141202402.
The previous prime is 1142141202347. The next prime is 1142141202443. The reversal of 1142141202403 is 3042021412411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1142141202403 - 213 = 1142141194211 is a prime.
It is a super-2 number, since 2×11421412024032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1142141202443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571070601201 + 571070601202.
It is an arithmetic number, because the mean of its divisors is an integer number (571070601202).
Almost surely, 21142141202403 is an apocalyptic number.
1142141202403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1142141202403 is an equidigital number, since it uses as much as digits as its factorization.
1142141202403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1142141202403 its reverse (3042021412411), we get a palindrome (4184162614814).
The spelling of 1142141202403 in words is "one trillion, one hundred forty-two billion, one hundred forty-one million, two hundred two thousand, four hundred three".
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