Base | Representation |
---|---|
bin | 110101001100000001… |
… | …0000000011100100111 |
3 | 101220211011201200002101 |
4 | 1222120002000130213 |
5 | 3332410233001042 |
6 | 124245530552531 |
7 | 11152321250143 |
oct | 1523002003447 |
9 | 356734650071 |
10 | 114219812647 |
11 | 44493119886 |
12 | 1a177b98747 |
13 | aa03821975 |
14 | 57577d6223 |
15 | 2e877dc6b7 |
hex | 1a98080727 |
114219812647 has 2 divisors, whose sum is σ = 114219812648. Its totient is φ = 114219812646.
The previous prime is 114219812639. The next prime is 114219812671. The reversal of 114219812647 is 746218912411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114219812647 - 23 = 114219812639 is a prime.
It is a super-2 number, since 2×1142198126472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114219812597 and 114219812606.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114219816647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57109906323 + 57109906324.
It is an arithmetic number, because the mean of its divisors is an integer number (57109906324).
Almost surely, 2114219812647 is an apocalyptic number.
114219812647 is a deficient number, since it is larger than the sum of its proper divisors (1).
114219812647 is an equidigital number, since it uses as much as digits as its factorization.
114219812647 is an evil number, because the sum of its binary digits is even.
The product of its digits is 193536, while the sum is 46.
The spelling of 114219812647 in words is "one hundred fourteen billion, two hundred nineteen million, eight hundred twelve thousand, six hundred forty-seven".
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