Base | Representation |
---|---|
bin | 10101010001100111… |
… | …11101111111100011 |
3 | 1002111000202022221022 |
4 | 22220303331333203 |
5 | 141343031131042 |
6 | 5125223520055 |
7 | 553023334661 |
oct | 125063757743 |
9 | 32430668838 |
10 | 11422130147 |
11 | 493154948a |
12 | 22692b902b |
13 | 1100516abc |
14 | 7a4d95c31 |
15 | 46cb74cd2 |
hex | 2a8cfdfe3 |
11422130147 has 2 divisors, whose sum is σ = 11422130148. Its totient is φ = 11422130146.
The previous prime is 11422130129. The next prime is 11422130173. The reversal of 11422130147 is 74103122411.
It is an a-pointer prime, because the next prime (11422130173) can be obtained adding 11422130147 to its sum of digits (26).
It is a weak prime.
It is an emirp because it is prime and its reverse (74103122411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11422130147 - 210 = 11422129123 is a prime.
It is not a weakly prime, because it can be changed into another prime (11422132147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5711065073 + 5711065074.
It is an arithmetic number, because the mean of its divisors is an integer number (5711065074).
Almost surely, 211422130147 is an apocalyptic number.
11422130147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11422130147 is an equidigital number, since it uses as much as digits as its factorization.
11422130147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 11422130147 its reverse (74103122411), we get a palindrome (85525252558).
The spelling of 11422130147 in words is "eleven billion, four hundred twenty-two million, one hundred thirty thousand, one hundred forty-seven".
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