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114222124042183 is a prime number
BaseRepresentation
bin11001111110001001101001…
…001000010000011111000111
3112222102112021012210221220101
4121332021221020100133013
5104432403402223322213
61042532530330544531
733026163466653463
oct3176115110203707
9488375235727811
10114222124042183
1133438370291343
121098901a298147
134b9713bb4ba81
14202c5477914a3
15d312a60c3bdd
hex67e2692107c7

114222124042183 has 2 divisors, whose sum is σ = 114222124042184. Its totient is φ = 114222124042182.

The previous prime is 114222124042153. The next prime is 114222124042199. The reversal of 114222124042183 is 381240421222411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114222124042183 - 217 = 114222123911111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114222124042153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57111062021091 + 57111062021092.

It is an arithmetic number, because the mean of its divisors is an integer number (57111062021092).

Almost surely, 2114222124042183 is an apocalyptic number.

114222124042183 is a deficient number, since it is larger than the sum of its proper divisors (1).

114222124042183 is an equidigital number, since it uses as much as digits as its factorization.

114222124042183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 49152, while the sum is 37.

Adding to 114222124042183 its reverse (381240421222411), we get a palindrome (495462545264594).

The spelling of 114222124042183 in words is "one hundred fourteen trillion, two hundred twenty-two billion, one hundred twenty-four million, forty-two thousand, one hundred eighty-three".