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114222124151273 is a prime number
BaseRepresentation
bin11001111110001001101001…
…001000101011000111101001
3112222102112021020000111112202
4121332021221020223013221
5104432403402240320043
61042532530333145545
733026163500616515
oct3176115110530751
9488375236014482
10114222124151273
11334383703562a6
121098901a32b2b5
134b9713bb89618
14202c5477bd145
15d312a60e61b8
hex67e26922b1e9

114222124151273 has 2 divisors, whose sum is σ = 114222124151274. Its totient is φ = 114222124151272.

The previous prime is 114222124151269. The next prime is 114222124151339. The reversal of 114222124151273 is 372151421222411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63047601823504 + 51174522327769 = 7940252^2 + 7153637^2 .

It is a cyclic number.

It is not a de Polignac number, because 114222124151273 - 22 = 114222124151269 is a prime.

It is not a weakly prime, because it can be changed into another prime (114222124181273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57111062075636 + 57111062075637.

It is an arithmetic number, because the mean of its divisors is an integer number (57111062075637).

Almost surely, 2114222124151273 is an apocalyptic number.

It is an amenable number.

114222124151273 is a deficient number, since it is larger than the sum of its proper divisors (1).

114222124151273 is an equidigital number, since it uses as much as digits as its factorization.

114222124151273 is an evil number, because the sum of its binary digits is even.

The product of its digits is 53760, while the sum is 38.

Adding to 114222124151273 its reverse (372151421222411), we get a palindrome (486373545373684).

The spelling of 114222124151273 in words is "one hundred fourteen trillion, two hundred twenty-two billion, one hundred twenty-four million, one hundred fifty-one thousand, two hundred seventy-three".