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114224425343459 is a prime number
BaseRepresentation
bin11001111110001011110010…
…010011000001100111100011
3112222102202012121010011202222
4121332023302103001213203
5104432423110341442314
61042533550535501255
733026304512464604
oct3176136223014743
9488382177104688
10114224425343459
1133439341311022
1210989560b2782b
134b9741785b2c2
14202c6c527bdab
15d3138d150c8e
hex67e2f24c19e3

114224425343459 has 2 divisors, whose sum is σ = 114224425343460. Its totient is φ = 114224425343458.

The previous prime is 114224425343417. The next prime is 114224425343599. The reversal of 114224425343459 is 954343524422411.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114224425343459 is a prime.

It is a super-3 number, since 3×1142244253434593 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 114224425343459.

It is not a weakly prime, because it can be changed into another prime (114224425043459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57112212671729 + 57112212671730.

It is an arithmetic number, because the mean of its divisors is an integer number (57112212671730).

Almost surely, 2114224425343459 is an apocalyptic number.

114224425343459 is a deficient number, since it is larger than the sum of its proper divisors (1).

114224425343459 is an equidigital number, since it uses as much as digits as its factorization.

114224425343459 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16588800, while the sum is 53.

The spelling of 114224425343459 in words is "one hundred fourteen trillion, two hundred twenty-four billion, four hundred twenty-five million, three hundred forty-three thousand, four hundred fifty-nine".