Base | Representation |
---|---|
bin | 11001111110001100100110… |
… | …101100000001000101100001 |
3 | 112222102211110212001022100111 |
4 | 121332030212230001011201 |
5 | 104432431410400410423 |
6 | 1042534214055051321 |
7 | 33026335344541603 |
oct | 3176144654010541 |
9 | 488384425038314 |
10 | 114225304310113 |
11 | 33439752487747 |
12 | 10989767370b41 |
13 | 4b9752799c109 |
14 | 202c769cc1173 |
15 | d313e03c560d |
hex | 67e326b01161 |
114225304310113 has 2 divisors, whose sum is σ = 114225304310114. Its totient is φ = 114225304310112.
The previous prime is 114225304310069. The next prime is 114225304310119. The reversal of 114225304310113 is 311013403522411.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102937095307264 + 11288209002849 = 10145792^2 + 3359793^2 .
It is a cyclic number.
It is not a de Polignac number, because 114225304310113 - 221 = 114225302212961 is a prime.
It is not a weakly prime, because it can be changed into another prime (114225304310119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57112652155056 + 57112652155057.
It is an arithmetic number, because the mean of its divisors is an integer number (57112652155057).
Almost surely, 2114225304310113 is an apocalyptic number.
It is an amenable number.
114225304310113 is a deficient number, since it is larger than the sum of its proper divisors (1).
114225304310113 is an equidigital number, since it uses as much as digits as its factorization.
114225304310113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 114225304310113 its reverse (311013403522411), we get a palindrome (425238707832524).
The spelling of 114225304310113 in words is "one hundred fourteen trillion, two hundred twenty-five billion, three hundred four million, three hundred ten thousand, one hundred thirteen".
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