Base | Representation |
---|---|
bin | 10101010001110000… |
… | …01101011100010001 |
3 | 1002111002211211010002 |
4 | 22220320031130101 |
5 | 141343322221001 |
6 | 5125303415345 |
7 | 553035645353 |
oct | 125070153421 |
9 | 32432754102 |
10 | 11423242001 |
11 | 4932138876 |
12 | 2269754555 |
13 | 1100815bc2 |
14 | 7a51a50d3 |
15 | 46cce446b |
hex | 2a8e0d711 |
11423242001 has 2 divisors, whose sum is σ = 11423242002. Its totient is φ = 11423242000.
The previous prime is 11423241979. The next prime is 11423242003. The reversal of 11423242001 is 10024232411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10045050625 + 1378191376 = 100225^2 + 37124^2 .
It is an emirp because it is prime and its reverse (10024232411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11423242001 is a prime.
Together with 11423242003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11423242003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5711621000 + 5711621001.
It is an arithmetic number, because the mean of its divisors is an integer number (5711621001).
Almost surely, 211423242001 is an apocalyptic number.
It is an amenable number.
11423242001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11423242001 is an equidigital number, since it uses as much as digits as its factorization.
11423242001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 11423242001 its reverse (10024232411), we get a palindrome (21447474412).
The spelling of 11423242001 in words is "eleven billion, four hundred twenty-three million, two hundred forty-two thousand, one".
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