Base | Representation |
---|---|
bin | 1010011000111101110001… |
… | …0100001010001100011011 |
3 | 1111110010101012101111200022 |
4 | 2212033130110022030123 |
5 | 2444132340130442334 |
6 | 40144041505501055 |
7 | 2256233503314365 |
oct | 246173424121433 |
9 | 44403335344608 |
10 | 11424014312219 |
11 | 370499628a533 |
12 | 134607334178b |
13 | 64b383cccca2 |
14 | 2b6cd4c1bd35 |
15 | 14c27146e82e |
hex | a63dc50a31b |
11424014312219 has 2 divisors, whose sum is σ = 11424014312220. Its totient is φ = 11424014312218.
The previous prime is 11424014312159. The next prime is 11424014312279. The reversal of 11424014312219 is 91221341042411.
It is a balanced prime because it is at equal distance from previous prime (11424014312159) and next prime (11424014312279).
It is an emirp because it is prime and its reverse (91221341042411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11424014312219 - 212 = 11424014308123 is a prime.
It is a super-2 number, since 2×114240143122192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11424014312279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712007156109 + 5712007156110.
It is an arithmetic number, because the mean of its divisors is an integer number (5712007156110).
Almost surely, 211424014312219 is an apocalyptic number.
11424014312219 is a deficient number, since it is larger than the sum of its proper divisors (1).
11424014312219 is an equidigital number, since it uses as much as digits as its factorization.
11424014312219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 35.
The spelling of 11424014312219 in words is "eleven trillion, four hundred twenty-four billion, fourteen million, three hundred twelve thousand, two hundred nineteen".
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