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114241131242009 is a prime number
BaseRepresentation
bin11001111110011011010110…
…000010111110001000011001
3112222111100022212012202100022
4121332123112002332020121
5104433211314044221014
61042545352353120225
733030435505334312
oct3176332602761031
9488440285182308
10114241131242009
1133445434364952
1210990843859075
134b98b7a93a685
14202d42bc81609
15d31a19ad1a8e
hex67e6d60be219

114241131242009 has 2 divisors, whose sum is σ = 114241131242010. Its totient is φ = 114241131242008.

The previous prime is 114241131241949. The next prime is 114241131242011. The reversal of 114241131242009 is 900242131142411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85935273136384 + 28305858105625 = 9270128^2 + 5320325^2 .

It is a cyclic number.

It is not a de Polignac number, because 114241131242009 - 220 = 114241130193433 is a prime.

Together with 114241131242011, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114241131242009.

It is not a weakly prime, because it can be changed into another prime (114241131142009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120565621004 + 57120565621005.

It is an arithmetic number, because the mean of its divisors is an integer number (57120565621005).

Almost surely, 2114241131242009 is an apocalyptic number.

It is an amenable number.

114241131242009 is a deficient number, since it is larger than the sum of its proper divisors (1).

114241131242009 is an equidigital number, since it uses as much as digits as its factorization.

114241131242009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 35.

The spelling of 114241131242009 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred thirty-one million, two hundred forty-two thousand, nine".