Base | Representation |
---|---|
bin | 11001111110011011010110… |
… | …001011010111010000000010 |
3 | 112222111100100000100112020022 |
4 | 121332123112023113100002 |
5 | 104433211320130121200 |
6 | 1042545352512213442 |
7 | 33030435533126366 |
oct | 3176332613272002 |
9 | 488440300315208 |
10 | 114241133442050 |
11 | 3344543562786a |
12 | 1099084453a282 |
13 | 4b98b7b22ab84 |
14 | 202d42c2952a6 |
15 | d31a19db8885 |
hex | 67e6d62d7402 |
114241133442050 has 12 divisors (see below), whose sum is σ = 212488508202306. Its totient is φ = 45696453376800.
The previous prime is 114241133442047. The next prime is 114241133442061. The reversal of 114241133442050 is 50244331142411.
It can be written as a sum of positive squares in 3 ways, for example, as 100982380902001 + 13258752540049 = 10048999^2 + 3641257^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 114241133442050.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1142411334371 + ... + 1142411334470.
Almost surely, 2114241133442050 is an apocalyptic number.
114241133442050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
114241133442050 is a deficient number, since it is larger than the sum of its proper divisors (98247374760256).
114241133442050 is a wasteful number, since it uses less digits than its factorization.
114241133442050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2284822668853 (or 2284822668848 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 114241133442050 its reverse (50244331142411), we get a palindrome (164485464584461).
The spelling of 114241133442050 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred thirty-three million, four hundred forty-two thousand, fifty".
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