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114242045550403 is a prime number
BaseRepresentation
bin11001111110011100001100…
…100010110001111101000011
3112222111102200120122102200011
4121332130030202301331003
5104433220202130103103
61042550023214005351
733030500246665411
oct3176341442617503
9488442616572604
10114242045550403
113344586347a321
1210990a59aa6857
134b98c951a3964
14202d4b74842b1
15d31a6eed7d6d
hex67e70c8b1f43

114242045550403 has 2 divisors, whose sum is σ = 114242045550404. Its totient is φ = 114242045550402.

The previous prime is 114242045550401. The next prime is 114242045550419. The reversal of 114242045550403 is 304055540242411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114242045550403 - 21 = 114242045550401 is a prime.

Together with 114242045550401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (114242045550401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121022775201 + 57121022775202.

It is an arithmetic number, because the mean of its divisors is an integer number (57121022775202).

Almost surely, 2114242045550403 is an apocalyptic number.

114242045550403 is a deficient number, since it is larger than the sum of its proper divisors (1).

114242045550403 is an equidigital number, since it uses as much as digits as its factorization.

114242045550403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384000, while the sum is 40.

Adding to 114242045550403 its reverse (304055540242411), we get a palindrome (418297585792814).

The spelling of 114242045550403 in words is "one hundred fourteen trillion, two hundred forty-two billion, forty-five million, five hundred fifty thousand, four hundred three".