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114242333141 is a prime number
BaseRepresentation
bin110101001100101011…
…1111010100111010101
3101220212202002211101202
41222121113322213111
53332432014130031
6124252053402245
711153013544436
oct1523127724725
9356782084352
10114242333141
11444a4900862
121a183639385
13aa083a83c1
14575a7b948d
152e8978a2cb
hex1a995fa9d5

114242333141 has 2 divisors, whose sum is σ = 114242333142. Its totient is φ = 114242333140.

The previous prime is 114242333059. The next prime is 114242333147. The reversal of 114242333141 is 141333242411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98049770641 + 16192562500 = 313129^2 + 127250^2 .

It is an emirp because it is prime and its reverse (141333242411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114242333141 - 210 = 114242332117 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114242333147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121166570 + 57121166571.

It is an arithmetic number, because the mean of its divisors is an integer number (57121166571).

Almost surely, 2114242333141 is an apocalyptic number.

It is an amenable number.

114242333141 is a deficient number, since it is larger than the sum of its proper divisors (1).

114242333141 is an equidigital number, since it uses as much as digits as its factorization.

114242333141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 29.

Adding to 114242333141 its reverse (141333242411), we get a palindrome (255575575552).

The spelling of 114242333141 in words is "one hundred fourteen billion, two hundred forty-two million, three hundred thirty-three thousand, one hundred forty-one".