Base | Representation |
---|---|
bin | 11001111110011101001000… |
… | …101011010111000100011011 |
3 | 112222111112021220000221210012 |
4 | 121332131020223113010123 |
5 | 104433224233413320124 |
6 | 1042550311253512135 |
7 | 33030534250231634 |
oct | 3176351053270433 |
9 | 488445256027705 |
10 | 114243054432539 |
11 | 33446230a0a40a |
12 | 1099109b94264b |
13 | 4b990c6200936 |
14 | 202d57146488b |
15 | d31acd870e0e |
hex | 67e748ad711b |
114243054432539 has 2 divisors, whose sum is σ = 114243054432540. Its totient is φ = 114243054432538.
The previous prime is 114243054432487. The next prime is 114243054432589. The reversal of 114243054432539 is 935234450342411.
It is an a-pointer prime, because the next prime (114243054432589) can be obtained adding 114243054432539 to its sum of digits (50).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114243054432539 - 224 = 114243037655323 is a prime.
It is not a weakly prime, because it can be changed into another prime (114243054432589) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57121527216269 + 57121527216270.
It is an arithmetic number, because the mean of its divisors is an integer number (57121527216270).
Almost surely, 2114243054432539 is an apocalyptic number.
114243054432539 is a deficient number, since it is larger than the sum of its proper divisors (1).
114243054432539 is an equidigital number, since it uses as much as digits as its factorization.
114243054432539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6220800, while the sum is 50.
The spelling of 114243054432539 in words is "one hundred fourteen trillion, two hundred forty-three billion, fifty-four million, four hundred thirty-two thousand, five hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •