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114244013441 is a prime number
BaseRepresentation
bin110101001100101111…
…0010100110110000001
3101220212212021012100002
41222121132110312001
53332432431412231
6124252153405345
711153034043325
oct1523136246601
9356785235302
10114244013441
11444a5849238
121a184109855
13aa0884616c
14575aad5985
152e899bd0cb
hex1a99794d81

114244013441 has 2 divisors, whose sum is σ = 114244013442. Its totient is φ = 114244013440.

The previous prime is 114244013423. The next prime is 114244013491. The reversal of 114244013441 is 144310442411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95927097841 + 18316915600 = 309721^2 + 135340^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114244013441 is a prime.

It is not a weakly prime, because it can be changed into another prime (114244013491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57122006720 + 57122006721.

It is an arithmetic number, because the mean of its divisors is an integer number (57122006721).

Almost surely, 2114244013441 is an apocalyptic number.

It is an amenable number.

114244013441 is a deficient number, since it is larger than the sum of its proper divisors (1).

114244013441 is an equidigital number, since it uses as much as digits as its factorization.

114244013441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 114244013441 its reverse (144310442411), we get a palindrome (258554455852).

The spelling of 114244013441 in words is "one hundred fourteen billion, two hundred forty-four million, thirteen thousand, four hundred forty-one".