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114245014241 is a prime number
BaseRepresentation
bin110101001100110001…
…0001001001011100001
3101220212221011001011202
41222121202021023201
53332433210423431
6124252231050545
711153045412161
oct1523142111341
9356787131152
10114245014241
11444a6372146
121a184510a55
13aa08b06857
14575acb65a1
152e89b198cb
hex1a998892e1

114245014241 has 2 divisors, whose sum is σ = 114245014242. Its totient is φ = 114245014240.

The previous prime is 114245014231. The next prime is 114245014243. The reversal of 114245014241 is 142410542411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112778430625 + 1466583616 = 335825^2 + 38296^2 .

It is a cyclic number.

It is not a de Polignac number, because 114245014241 - 222 = 114240819937 is a prime.

Together with 114245014243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (114245014243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57122507120 + 57122507121.

It is an arithmetic number, because the mean of its divisors is an integer number (57122507121).

Almost surely, 2114245014241 is an apocalyptic number.

It is an amenable number.

114245014241 is a deficient number, since it is larger than the sum of its proper divisors (1).

114245014241 is an equidigital number, since it uses as much as digits as its factorization.

114245014241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5120, while the sum is 29.

Adding to 114245014241 its reverse (142410542411), we get a palindrome (256655556652).

The spelling of 114245014241 in words is "one hundred fourteen billion, two hundred forty-five million, fourteen thousand, two hundred forty-one".