Base | Representation |
---|---|
bin | 110101001100110001… |
… | …0001001001011100001 |
3 | 101220212221011001011202 |
4 | 1222121202021023201 |
5 | 3332433210423431 |
6 | 124252231050545 |
7 | 11153045412161 |
oct | 1523142111341 |
9 | 356787131152 |
10 | 114245014241 |
11 | 444a6372146 |
12 | 1a184510a55 |
13 | aa08b06857 |
14 | 575acb65a1 |
15 | 2e89b198cb |
hex | 1a998892e1 |
114245014241 has 2 divisors, whose sum is σ = 114245014242. Its totient is φ = 114245014240.
The previous prime is 114245014231. The next prime is 114245014243. The reversal of 114245014241 is 142410542411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112778430625 + 1466583616 = 335825^2 + 38296^2 .
It is a cyclic number.
It is not a de Polignac number, because 114245014241 - 222 = 114240819937 is a prime.
Together with 114245014243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (114245014243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57122507120 + 57122507121.
It is an arithmetic number, because the mean of its divisors is an integer number (57122507121).
Almost surely, 2114245014241 is an apocalyptic number.
It is an amenable number.
114245014241 is a deficient number, since it is larger than the sum of its proper divisors (1).
114245014241 is an equidigital number, since it uses as much as digits as its factorization.
114245014241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5120, while the sum is 29.
Adding to 114245014241 its reverse (142410542411), we get a palindrome (256655556652).
The spelling of 114245014241 in words is "one hundred fourteen billion, two hundred forty-five million, fourteen thousand, two hundred forty-one".
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