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114250040411501 is a prime number
BaseRepresentation
bin11001111110100011101001…
…000100110000010101101101
3112222112012022202101110022202
4121332203221010300111231
5104433333040321132001
61042553424411351245
733031202336123351
oct3176435104602555
9488465282343282
10114250040411501
1133449196357845
121099250b452525
134b9996a6379b7
14202da351b1461
15d31d8bd1a96b
hex67e8e913056d

114250040411501 has 2 divisors, whose sum is σ = 114250040411502. Its totient is φ = 114250040411500.

The previous prime is 114250040411449. The next prime is 114250040411519. The reversal of 114250040411501 is 105114040052411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105323031815401 + 8927008596100 = 10262701^2 + 2987810^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114250040411501 is a prime.

It is a super-2 number, since 2×1142500404115012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114250040410501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57125020205750 + 57125020205751.

It is an arithmetic number, because the mean of its divisors is an integer number (57125020205751).

Almost surely, 2114250040411501 is an apocalyptic number.

It is an amenable number.

114250040411501 is a deficient number, since it is larger than the sum of its proper divisors (1).

114250040411501 is an equidigital number, since it uses as much as digits as its factorization.

114250040411501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3200, while the sum is 29.

Adding to 114250040411501 its reverse (105114040052411), we get a palindrome (219364080463912).

The spelling of 114250040411501 in words is "one hundred fourteen trillion, two hundred fifty billion, forty million, four hundred eleven thousand, five hundred one".