Base | Representation |
---|---|
bin | 11001111110100110111010… |
… | …011101000001001010000011 |
3 | 112222112112101120100002221101 |
4 | 121332212322131001022003 |
5 | 104433412234110204422 |
6 | 1042555205135035231 |
7 | 33031355362326352 |
oct | 3176467235011203 |
9 | 488475346302841 |
10 | 114253553209987 |
11 | 3344a729226294 |
12 | 1099312b96bb17 |
13 | 4b9a0aa335899 |
14 | 202dc89941999 |
15 | d31ee5404c27 |
hex | 67e9ba741283 |
114253553209987 has 2 divisors, whose sum is σ = 114253553209988. Its totient is φ = 114253553209986.
The previous prime is 114253553209967. The next prime is 114253553210039. The reversal of 114253553209987 is 789902355352411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114253553209987 - 223 = 114253544821379 is a prime.
It is a super-4 number, since 4×1142535532099874 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (114253553209967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57126776604993 + 57126776604994.
It is an arithmetic number, because the mean of its divisors is an integer number (57126776604994).
Almost surely, 2114253553209987 is an apocalyptic number.
114253553209987 is a deficient number, since it is larger than the sum of its proper divisors (1).
114253553209987 is an equidigital number, since it uses as much as digits as its factorization.
114253553209987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648000, while the sum is 64.
The spelling of 114253553209987 in words is "one hundred fourteen trillion, two hundred fifty-three billion, five hundred fifty-three million, two hundred nine thousand, nine hundred eighty-seven".
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