114255131 has 2 divisors, whose sum is σ = 114255132. Its totient is φ = 114255130.

The previous prime is 114255109. The next prime is 114255133. The reversal of 114255131 is 131552411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114255131 - 2⁶ = 114255067 is a prime.

It is a super-2 number, since 2×114255131² = 26108469919654322, which contains 22 as substring.

Together with 114255133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 114255097 and 114255106.

It is not a weakly prime, because it can be changed into another prime (114255133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127565 + 57127566.

It is an arithmetic number, because the mean of its divisors is an integer number (57127566).

Almost surely, 2^114255131 is an apocalyptic number.

114255131 is a deficient number, since it is larger than the sum of its proper divisors (1).

114255131 is an equidigital number, since it uses as much as digits as its factorization.

114255131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 600, while the sum is 23.

The square root of 114255131 is about 10689.0191785776. The cubic root of 114255131 is about 485.2422087053.

The spelling of 114255131 in words is "one hundred fourteen million, two hundred fifty-five thousand, one hundred thirty-one".