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11426437133 is a prime number
BaseRepresentation
bin10101010010001000…
…11001100000001101
31002111022212011000022
422221010121200031
5141400131442013
65125500111525
7553105053536
oct125104314015
932438764008
1011426437133
114933a20381
12226a8355a5
131101394307
147a579768d
1546d226008
hex2a911980d

11426437133 has 2 divisors, whose sum is σ = 11426437134. Its totient is φ = 11426437132.

The previous prime is 11426437129. The next prime is 11426437177. The reversal of 11426437133 is 33173462411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10725087844 + 701349289 = 103562^2 + 26483^2 .

It is a cyclic number.

It is not a de Polignac number, because 11426437133 - 22 = 11426437129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11426437093 and 11426437102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11426437933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5713218566 + 5713218567.

It is an arithmetic number, because the mean of its divisors is an integer number (5713218567).

Almost surely, 211426437133 is an apocalyptic number.

It is an amenable number.

11426437133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11426437133 is an equidigital number, since it uses as much as digits as its factorization.

11426437133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 36288, while the sum is 35.

Adding to 11426437133 its reverse (33173462411), we get a palindrome (44599899544).

The spelling of 11426437133 in words is "eleven billion, four hundred twenty-six million, four hundred thirty-seven thousand, one hundred thirty-three".