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114280711294471 is a prime number
BaseRepresentation
bin11001111111000000001101…
…001100111000111000000111
3112222122010111021001202010021
4121333000031030320320013
5104434333344042410341
61043015500051040011
733033336363253261
oct3177001514707007
9488563437052107
10114280711294471
11334601a5263107
121099844aba0007
134b9c8179b6067
142031304774b31
15d32a847b49d1
hex67f00d338e07

114280711294471 has 2 divisors, whose sum is σ = 114280711294472. Its totient is φ = 114280711294470.

The previous prime is 114280711294439. The next prime is 114280711294489. The reversal of 114280711294471 is 174492117082411.

It is a strong prime.

It is an emirp because it is prime and its reverse (174492117082411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114280711294471 - 25 = 114280711294439 is a prime.

It is a super-3 number, since 3×1142807112944713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114280711297471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57140355647235 + 57140355647236.

It is an arithmetic number, because the mean of its divisors is an integer number (57140355647236).

Almost surely, 2114280711294471 is an apocalyptic number.

114280711294471 is a deficient number, since it is larger than the sum of its proper divisors (1).

114280711294471 is an equidigital number, since it uses as much as digits as its factorization.

114280711294471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 903168, while the sum is 52.

The spelling of 114280711294471 in words is "one hundred fourteen trillion, two hundred eighty billion, seven hundred eleven million, two hundred ninety-four thousand, four hundred seventy-one".