Base | Representation |
---|---|
bin | 11001111111010010001100… |
… | …001011001101011101110100 |
3 | 112222200222100000111021101221 |
4 | 121333102030023031131310 |
5 | 104440142420441231012 |
6 | 1043032412134200124 |
7 | 33034622040562006 |
oct | 3177221413153564 |
9 | 488628300437357 |
10 | 114300021430132 |
11 | 3346840433590a |
12 | 109a0139ab3044 |
13 | 4ba15a448cb35 |
14 | 20322171a0376 |
15 | d33314bb1507 |
hex | 67f48c2cd774 |
114300021430132 has 12 divisors (see below), whose sum is σ = 200091205250496. Its totient is φ = 57131105644280.
The previous prime is 114300021430123. The next prime is 114300021430141. The reversal of 114300021430132 is 231034120003411.
It is an interprime number because it is at equal distance from previous prime (114300021430123) and next prime (114300021430141).
It is a junction number, because it is equal to n+sod(n) for n = 114300021430097 and 114300021430106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4726254094 + ... + 4726278277.
It is an arithmetic number, because the mean of its divisors is an integer number (16674267104208).
Almost surely, 2114300021430132 is an apocalyptic number.
It is an amenable number.
114300021430132 is a deficient number, since it is larger than the sum of its proper divisors (85791183820364).
114300021430132 is a wasteful number, since it uses less digits than its factorization.
114300021430132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9452535398 (or 9452535396 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 114300021430132 its reverse (231034120003411), we get a palindrome (345334141433543).
The spelling of 114300021430132 in words is "one hundred fourteen trillion, three hundred billion, twenty-one million, four hundred thirty thousand, one hundred thirty-two".
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