Base | Representation |
---|---|
bin | 1010011001010100000111… |
… | …1011101010100100000011 |
3 | 1111110200212100010001121111 |
4 | 2212111001323222210003 |
5 | 2444232132104301111 |
6 | 40150513114504151 |
7 | 2256535256052616 |
oct | 246250173524403 |
9 | 44420770101544 |
10 | 11430014134531 |
11 | 3707494aa9873 |
12 | 1347268735057 |
13 | 64bacc035bc5 |
14 | 2b73039c217d |
15 | 14c4c306ea21 |
hex | a6541eea903 |
11430014134531 has 2 divisors, whose sum is σ = 11430014134532. Its totient is φ = 11430014134530.
The previous prime is 11430014134519. The next prime is 11430014134549. The reversal of 11430014134531 is 13543141003411.
It is a weak prime.
It is an emirp because it is prime and its reverse (13543141003411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11430014134531 - 215 = 11430014101763 is a prime.
It is a super-2 number, since 2×114300141345312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11430014134493 and 11430014134502.
It is not a weakly prime, because it can be changed into another prime (11430014534531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715007067265 + 5715007067266.
It is an arithmetic number, because the mean of its divisors is an integer number (5715007067266).
Almost surely, 211430014134531 is an apocalyptic number.
11430014134531 is a deficient number, since it is larger than the sum of its proper divisors (1).
11430014134531 is an equidigital number, since it uses as much as digits as its factorization.
11430014134531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 11430014134531 its reverse (13543141003411), we get a palindrome (24973155137942).
The spelling of 11430014134531 in words is "eleven trillion, four hundred thirty billion, fourteen million, one hundred thirty-four thousand, five hundred thirty-one".
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