Base | Representation |
---|---|
bin | 11001111111010010011101… |
… | …101000000111101101001111 |
3 | 112222201000002102102121111122 |
4 | 121333102131220013231033 |
5 | 104440144020420041031 |
6 | 1043032501153511155 |
7 | 33034632224345564 |
oct | 3177223550075517 |
9 | 488630072377448 |
10 | 114300314221391 |
11 | 33468544636261 |
12 | 109a01bbb724bb |
13 | 4ba16200356bc |
14 | 203224401886b |
15 | d3333074947b |
hex | 67f49da07b4f |
114300314221391 has 2 divisors, whose sum is σ = 114300314221392. Its totient is φ = 114300314221390.
The previous prime is 114300314221339. The next prime is 114300314221447. The reversal of 114300314221391 is 193122413003411.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114300314221391 is a prime.
It is a super-2 number, since 2×1143003142213912 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114300314223391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150157110695 + 57150157110696.
It is an arithmetic number, because the mean of its divisors is an integer number (57150157110696).
Almost surely, 2114300314221391 is an apocalyptic number.
114300314221391 is a deficient number, since it is larger than the sum of its proper divisors (1).
114300314221391 is an equidigital number, since it uses as much as digits as its factorization.
114300314221391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 114300314221391 in words is "one hundred fourteen trillion, three hundred billion, three hundred fourteen million, two hundred twenty-one thousand, three hundred ninety-one".
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