Base | Representation |
---|---|
bin | 11001111111010010011101… |
… | …101000000111110110101111 |
3 | 112222201000002102102122100011 |
4 | 121333102131220013312233 |
5 | 104440144020420100444 |
6 | 1043032501153514051 |
7 | 33034632224350423 |
oct | 3177223550076657 |
9 | 488630072378304 |
10 | 114300314221999 |
11 | 33468544636764 |
12 | 109a01bbb72927 |
13 | 4ba1620035a69 |
14 | 2032244018b83 |
15 | d33330749734 |
hex | 67f49da07daf |
114300314221999 has 2 divisors, whose sum is σ = 114300314222000. Its totient is φ = 114300314221998.
The previous prime is 114300314221969. The next prime is 114300314222011. The reversal of 114300314221999 is 999122413003411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114300314221999 - 223 = 114300305833391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114300314221969) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150157110999 + 57150157111000.
It is an arithmetic number, because the mean of its divisors is an integer number (57150157111000).
Almost surely, 2114300314221999 is an apocalyptic number.
114300314221999 is a deficient number, since it is larger than the sum of its proper divisors (1).
114300314221999 is an equidigital number, since it uses as much as digits as its factorization.
114300314221999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 419904, while the sum is 49.
The spelling of 114300314221999 in words is "one hundred fourteen trillion, three hundred billion, three hundred fourteen million, two hundred twenty-one thousand, nine hundred ninety-nine".
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