11430041741101 has 2 divisors, whose sum is σ = 11430041741102. Its totient is φ = 11430041741100.

The previous prime is 11430041741081. The next prime is 11430041741119. The reversal of 11430041741101 is 10114714003411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9127921350025 + 2302120391076 = 3021245^2 + 1517274^2 .

It is an emirp because it is prime and its reverse (10114714003411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11430041741101 - 2²⁵ = 11430008186669 is a prime.

It is a super-2 number, since 2×11430041741101² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11430041741101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11430041741171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715020870550 + 5715020870551.

It is an arithmetic number, because the mean of its divisors is an integer number (5715020870551).

Almost surely, 2^{11430041741101} is an apocalyptic number.

It is an amenable number.

11430041741101 is a deficient number, since it is larger than the sum of its proper divisors (1).

11430041741101 is an equidigital number, since it uses as much as digits as its factorization.

11430041741101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 28.

Adding to 11430041741101 its reverse (10114714003411), we get a palindrome (21544755744512).

The spelling of 11430041741101 in words is "eleven trillion, four hundred thirty billion, forty-one million, seven hundred forty-one thousand, one hundred one".