Base | Representation |
---|---|
bin | 11001111111010010101100… |
… | …000000001001011101100001 |
3 | 112222201000201020020210210212 |
4 | 121333102230000021131201 |
5 | 104440200014140313212 |
6 | 1043032541131103505 |
7 | 33034641213343364 |
oct | 3177225400113541 |
9 | 488630636223725 |
10 | 114300555401057 |
11 | 334686587950a3 |
12 | 109a02688a1b95 |
13 | 4ba165acaa46c |
14 | 203226807a0db |
15 | d333469d9e22 |
hex | 67f4ac009761 |
114300555401057 has 2 divisors, whose sum is σ = 114300555401058. Its totient is φ = 114300555401056.
The previous prime is 114300555401047. The next prime is 114300555401171. The reversal of 114300555401057 is 750104555003411.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99605170497121 + 14695384903936 = 9980239^2 + 3833456^2 .
It is a cyclic number.
It is not a de Polignac number, because 114300555401057 - 212 = 114300555396961 is a prime.
It is not a weakly prime, because it can be changed into another prime (114300555401047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150277700528 + 57150277700529.
It is an arithmetic number, because the mean of its divisors is an integer number (57150277700529).
Almost surely, 2114300555401057 is an apocalyptic number.
It is an amenable number.
114300555401057 is a deficient number, since it is larger than the sum of its proper divisors (1).
114300555401057 is an equidigital number, since it uses as much as digits as its factorization.
114300555401057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 210000, while the sum is 41.
The spelling of 114300555401057 in words is "one hundred fourteen trillion, three hundred billion, five hundred fifty-five million, four hundred one thousand, fifty-seven".
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