Base | Representation |
---|---|
bin | 11001111111010011001110… |
… | …011001101010001011011011 |
3 | 112222201002012110012011221201 |
4 | 121333103032121222023123 |
5 | 104440202204410422021 |
6 | 1043033114304415031 |
7 | 33034661421620422 |
oct | 3177231631521333 |
9 | 488632173164851 |
10 | 114301132514011 |
11 | 33468924530653 |
12 | 109a03aa017477 |
13 | 4ba1720721811 |
14 | 20322c09862b9 |
15 | d3337c4d6591 |
hex | 67f4ce66a2db |
114301132514011 has 2 divisors, whose sum is σ = 114301132514012. Its totient is φ = 114301132514010.
The previous prime is 114301132514003. The next prime is 114301132514081. The reversal of 114301132514011 is 110415231103411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114301132514011 - 23 = 114301132514003 is a prime.
It is a super-2 number, since 2×1143011325140112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114301132514081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150566257005 + 57150566257006.
It is an arithmetic number, because the mean of its divisors is an integer number (57150566257006).
Almost surely, 2114301132514011 is an apocalyptic number.
114301132514011 is a deficient number, since it is larger than the sum of its proper divisors (1).
114301132514011 is an equidigital number, since it uses as much as digits as its factorization.
114301132514011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 28.
Adding to 114301132514011 its reverse (110415231103411), we get a palindrome (224716363617422).
The spelling of 114301132514011 in words is "one hundred fourteen trillion, three hundred one billion, one hundred thirty-two million, five hundred fourteen thousand, eleven".
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