Base | Representation |
---|---|
bin | 1010011001010101100100… |
… | …0011101101111001111111 |
3 | 1111110201212101011211110102 |
4 | 2212111121003231321333 |
5 | 2444233430420340333 |
6 | 40151015414431315 |
7 | 2256551006641532 |
oct | 246253103557177 |
9 | 44421771154412 |
10 | 11430402121343 |
11 | 370767400a027 |
12 | 134735666253b |
13 | 64bb6152c4ba |
14 | 2b733d33aa19 |
15 | 14c4e715dae8 |
hex | a65590ede7f |
11430402121343 has 2 divisors, whose sum is σ = 11430402121344. Its totient is φ = 11430402121342.
The previous prime is 11430402121339. The next prime is 11430402121357. The reversal of 11430402121343 is 34312120403411.
It is a weak prime.
It is an emirp because it is prime and its reverse (34312120403411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11430402121343 - 22 = 11430402121339 is a prime.
It is a super-2 number, since 2×114304021213432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11430402121373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715201060671 + 5715201060672.
It is an arithmetic number, because the mean of its divisors is an integer number (5715201060672).
Almost surely, 211430402121343 is an apocalyptic number.
11430402121343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11430402121343 is an equidigital number, since it uses as much as digits as its factorization.
11430402121343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 11430402121343 its reverse (34312120403411), we get a palindrome (45742522524754).
The spelling of 11430402121343 in words is "eleven trillion, four hundred thirty billion, four hundred two million, one hundred twenty-one thousand, three hundred forty-three".
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