Base | Representation |
---|---|
bin | 11001111111011100111010… |
… | …010100110010111111110100 |
3 | 112222202002001021202101000222 |
4 | 121333130322110302333310 |
5 | 104440340004434111312 |
6 | 1043041554321353512 |
7 | 33035510232351422 |
oct | 3177347224627764 |
9 | 488662037671028 |
10 | 114311533113332 |
11 | 3347228138a885 |
12 | 109a2411198898 |
13 | 4ba26ba4002b9 |
14 | 20329c9dc8112 |
15 | d3378a625672 |
hex | 67f73a532ff4 |
114311533113332 has 48 divisors (see below), whose sum is σ = 220841754255360. Its totient is φ = 51529742433792.
The previous prime is 114311533113209. The next prime is 114311533113343. The reversal of 114311533113332 is 233311335113411.
It is a super-2 number, since 2×1143115331133322 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114311533113292 and 114311533113301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 227967308 + ... + 228468195.
It is an arithmetic number, because the mean of its divisors is an integer number (4600869880320).
Almost surely, 2114311533113332 is an apocalyptic number.
It is an amenable number.
114311533113332 is a deficient number, since it is larger than the sum of its proper divisors (106530221142028).
114311533113332 is a wasteful number, since it uses less digits than its factorization.
114311533113332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 456435680 (or 456435678 counting only the distinct ones).
The product of its digits is 29160, while the sum is 35.
Adding to 114311533113332 its reverse (233311335113411), we get a palindrome (347622868226743).
The spelling of 114311533113332 in words is "one hundred fourteen trillion, three hundred eleven billion, five hundred thirty-three million, one hundred thirteen thousand, three hundred thirty-two".
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