Base | Representation |
---|---|
bin | 10101010010101101… |
… | …00100100111001111 |
3 | 1002111122211012010101 |
4 | 22221112210213033 |
5 | 141402341414411 |
6 | 5130150151531 |
7 | 553163415202 |
oct | 125126444717 |
9 | 32448735111 |
10 | 11431201231 |
11 | 493668474a |
12 | 22703525a7 |
13 | 11023718c8 |
14 | 7a6277939 |
15 | 46d8678c1 |
hex | 2a95a49cf |
11431201231 has 2 divisors, whose sum is σ = 11431201232. Its totient is φ = 11431201230.
The previous prime is 11431201163. The next prime is 11431201241. The reversal of 11431201231 is 13210213411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11431201231 - 29 = 11431200719 is a prime.
It is a super-2 number, since 2×114312012312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11431201199 and 11431201208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11431201241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715600615 + 5715600616.
It is an arithmetic number, because the mean of its divisors is an integer number (5715600616).
Almost surely, 211431201231 is an apocalyptic number.
11431201231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11431201231 is an equidigital number, since it uses as much as digits as its factorization.
11431201231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11431201231 its reverse (13210213411), we get a palindrome (24641414642).
The spelling of 11431201231 in words is "eleven billion, four hundred thirty-one million, two hundred one thousand, two hundred thirty-one".
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