Base | Representation |
---|---|
bin | 1010011001011000100101… |
… | …1001001000111011001010 |
3 | 1111110210221220001221101202 |
4 | 2212112021121020323022 |
5 | 2444242111014342102 |
6 | 40151232103344202 |
7 | 2256610054445015 |
oct | 246261131107312 |
9 | 44423856057352 |
10 | 11431213043402 |
11 | 3707a4a82a849 |
12 | 1347542152062 |
13 | 64bc60537839 |
14 | 2b73b8d0a37c |
15 | 14c543441e02 |
hex | a6589648eca |
11431213043402 has 32 divisors (see below), whose sum is σ = 18065886753600. Its totient is φ = 5409806151168.
The previous prime is 11431213043363. The next prime is 11431213043413. The reversal of 11431213043402 is 20434031213411.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 238937828 + ... + 238985664.
It is an arithmetic number, because the mean of its divisors is an integer number (564558961050).
Almost surely, 211431213043402 is an apocalyptic number.
11431213043402 is a deficient number, since it is larger than the sum of its proper divisors (6634673710198).
11431213043402 is a wasteful number, since it uses less digits than its factorization.
11431213043402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53510.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 11431213043402 its reverse (20434031213411), we get a palindrome (31865244256813).
The spelling of 11431213043402 in words is "eleven trillion, four hundred thirty-one billion, two hundred thirteen million, forty-three thousand, four hundred two".
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