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114312521155013 is a prime number
BaseRepresentation
bin11001111111011101110101…
…001101111000000111000101
3112222202011121010221002102022
4121333131311031320013011
5104440344020403430023
61043042240334452525
733035543560515416
oct3177356515700705
9488664533832368
10114312521155013
1133472739086155
12109a2648064145
134ba281701144c
142032a8130180d
15d337e72437c8
hex67f7753781c5

114312521155013 has 2 divisors, whose sum is σ = 114312521155014. Its totient is φ = 114312521155012.

The previous prime is 114312521154977. The next prime is 114312521155033. The reversal of 114312521155013 is 310551125213411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113087421942049 + 1225099212964 = 10634257^2 + 1106842^2 .

It is a cyclic number.

It is not a de Polignac number, because 114312521155013 - 28 = 114312521154757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114312521155033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57156260577506 + 57156260577507.

It is an arithmetic number, because the mean of its divisors is an integer number (57156260577507).

Almost surely, 2114312521155013 is an apocalyptic number.

It is an amenable number.

114312521155013 is a deficient number, since it is larger than the sum of its proper divisors (1).

114312521155013 is an equidigital number, since it uses as much as digits as its factorization.

114312521155013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 35.

Adding to 114312521155013 its reverse (310551125213411), we get a palindrome (424863646368424).

The spelling of 114312521155013 in words is "one hundred fourteen trillion, three hundred twelve billion, five hundred twenty-one million, one hundred fifty-five thousand, thirteen".