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11431254467 is a prime number
BaseRepresentation
bin10101010010101101…
…10001100111000011
31002111122220220011002
422221112301213003
5141402400120332
65130151242215
7553164026333
oct125126614703
932448826132
1011431254467
114936710746
12227037936b
13110238cbc9
147a628d0c3
1546d878562
hex2a95b19c3

11431254467 has 2 divisors, whose sum is σ = 11431254468. Its totient is φ = 11431254466.

The previous prime is 11431254407. The next prime is 11431254473. The reversal of 11431254467 is 76445213411.

11431254467 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11431254467 - 218 = 11430992323 is a prime.

It is a super-3 number, since 3×114312544673 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11431254467.

It is not a weakly prime, because it can be changed into another prime (11431254407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715627233 + 5715627234.

It is an arithmetic number, because the mean of its divisors is an integer number (5715627234).

Almost surely, 211431254467 is an apocalyptic number.

11431254467 is a deficient number, since it is larger than the sum of its proper divisors (1).

11431254467 is an equidigital number, since it uses as much as digits as its factorization.

11431254467 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 80640, while the sum is 38.

Adding to 11431254467 its reverse (76445213411), we get a palindrome (87876467878).

The spelling of 11431254467 in words is "eleven billion, four hundred thirty-one million, two hundred fifty-four thousand, four hundred sixty-seven".