Base | Representation |
---|---|
bin | 1010011001011000111101… |
… | …0101001011001100110111 |
3 | 1111110211012211112100220012 |
4 | 2212112033111023030313 |
5 | 2444242312020324242 |
6 | 40151250022530435 |
7 | 2256612404313101 |
oct | 246261725131467 |
9 | 44424184470805 |
10 | 11431312667447 |
11 | 3707aa0a94872 |
12 | 134756b596a1b |
13 | 64bc7807918a |
14 | 2b73c8240571 |
15 | 14c54c070282 |
hex | a658f54b337 |
11431312667447 has 2 divisors, whose sum is σ = 11431312667448. Its totient is φ = 11431312667446.
The previous prime is 11431312667389. The next prime is 11431312667569. The reversal of 11431312667447 is 74476621313411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11431312667447 - 216 = 11431312601911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11431312667395 and 11431312667404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11431312660447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715656333723 + 5715656333724.
It is an arithmetic number, because the mean of its divisors is an integer number (5715656333724).
Almost surely, 211431312667447 is an apocalyptic number.
11431312667447 is a deficient number, since it is larger than the sum of its proper divisors (1).
11431312667447 is an equidigital number, since it uses as much as digits as its factorization.
11431312667447 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2032128, while the sum is 50.
The spelling of 11431312667447 in words is "eleven trillion, four hundred thirty-one billion, three hundred twelve million, six hundred sixty-seven thousand, four hundred forty-seven".
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